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If the solubility product of CuS is 6×10-16 , calculate the maximum molarity of CuS in aqueous solution. Select the correct answer from above options

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Correct Answer - S=2.45×10-8mol-1 Maximum molarity of CuS in aqueous solution is the solubility of CuS in molL-1 . Let S is the solubility of CuS in molL(-1) , then CuS⇔Cu2++S2- Ksp=[Cu2+][S2-] =S×S ltbr. =S2mol2L-2 ∴S= √ Ksp = √ 6×10-16 2.45×10-8molL-1

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