Correct Answer - S=2.45×10-8mol-1
Maximum molarity of CuS
in aqueous solution is the solubility of CuS
in molL-1
. Let S
is the solubility of CuS
in molL(-1)
, then
CuS⇔Cu2++S2-
Ksp=[Cu2+][S2-]
=S×S
ltbr. =S2mol2L-2
∴S=
√
Ksp
=
√
6×10-16
2.45×10-8molL-1