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How muCHM CHMarge is required for the following reductions : a.1molofAl3+→Al b. 1molofCu2+→Cu c. 1molofMnO c- 4 to Mn2+? Select the correct answer from above options

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Correct Answer - a.289500C ,b.193000C , c.482500C . a. Al3++3e-→Al 1molofAl=3F =3×96500 =289500C b. Cu2++2e-→Cu 1molofCu=2F =2×06500 =193000C c. MnO c- 4 +5e-→Mn2+ 1molofMnO c- 4 =5F =5×96500C =482500C

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