Question

A reaction is first order in A secod order in B : (i) write differential rate equation. (ii) How is the rate affected when the concentration of B is tripled ? (iii) How is the rate affected when the concentration of both A and B is doubled? Select the correct answer from above options

Answer 1

Correct Answer - a.r=k[A][B]2 b. Rate becomes 9 times. a. r=k[A][B]2 b. r2=k[A][B]2 r2=k[A][3B]2 r2 r1 =[3]2,r2=9r1 Rate becomes nine times. c. r1=k[A][B]2 r2=k[2A][2B]2 r2 r1 =2×(2)2 r2=8r1 Rate becomes eight times.