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The probabilities that a typist will make 0, 1, 2, 3, 4, 5 or more mistakes in typing a report are, respectively, 0.12, 0.25, 0.36, 0.14, 0.08, 0.11.

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State whether the statement are True or False. The probabilities that a typist will make 0, 1, 2, 3, 4, 5 or more mistakes in typing a report are, respectively, 0.12, 0.25, 0.36, 0.14, 0.08, 0.11. Select the correct answer from above options

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Let A be the event that typist will make 0 mistake in typing a report B be the event that typist will make 1 mistake in typing a report C be the event that typist will make 2 mistakes in typing a report D be the event that typist will make 3 mistakes in typing a report E be the event that typist will make 4 mistakes in typing a report F be the event that typist will make 5 mistakes in typing a report Then, we have P(A) = 0.12, P(B) = 0.25, P(C) = 0.36, P(D) = 0.14, P(E) = 0.08 and P(F) = 0.11 We know that, Sum of all probabilities = 1 ∴ P(A) + P(B) + P(C) + P(D) + P(E) + P(F) = 0.12 + 0.25 + 0.36 + 0.14 + 0.08 + 0.11 = 1.06 > 1 Hence, the given statement is False.

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