Correct Answer - D
Let
H
i
H
denote the event of getting a head in
i
t
h
i
toss and
T
i
T
denote the event of getting a tail in
i
t
h
i
toss. Then, Required probability.
=
P
{
(
H
1
∩
H
2
∩
H
3
∩
H
4
∩
T
5
)
∪
(
T
1
∩
T
2
∩
T
3
∩
T
4
∩
H
5
)
}
=
=
P
(
H
1
∩
H
2
∩
H
3
∩
H
4
∩
T
5
)
+
P
(
T
1
∩
T
2
∩
T
3
∩
T
4
∩
∩
H
5
)
=
=
P
(
H
1
)
P
(
H
2
)
P
(
H
3
)
P
(
H
4
)
P
(
T
5
)
+
P
(
T
1
)
P
(
T
2
)
P
(
T
3
)
P
(
T
4
)
P
(
H
5
)
=
−
(
1
2
)
5
+
(
1
2
)
5
=
1
16
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