Correct Answer - C
Out of first 30 natural numbers, three natural numbers can be chosen in
.
30
C
3
.
ways.
If the minimum and maximum of the numbers chosen are 9 and 25 respectively, then we have to select a number from the remaining 15 numbers i.e. 10,11,..,.., 24.
∴
∴
Favourable number of elementary events
=
.
15
C
1
=
.
Hence, required probability
=
.
15
C
1
.
30
C
3
=
3
812
=