Correct Answer - A
Out of integers from 1 to 11, there are 5 even integers and 6 odd integers.
Consider the following events :
A= Both the numbers chosen are odd,
B=The sum of the numbers chosen is even.
∴
Required probability
=P(A/B)
=Probability that the two numbers chosen are odd if it is given that the sum of the sum of the numbers chosen is even.
=
.5C2
.5C2+.6C2
=
3
5