Correct Answer - A
We have,
P
(
¯¯¯¯¯¯¯¯¯¯
A
∪
B
)
=
1
6
,
P
(
A
∩
B
)
=
1
4
and
P
(
¯¯¯
A
)
=
1
4
P
⇒
1
−
P
(
A
∪
B
)
=
1
6
⇒
(
A
∪
B
)
=
5
6
⇒
⇒
P
(
A
)
+
P
(
B
)
−
P
(
A
∩
B
)
=
5
6
⇒
3
4
+
P
(
B
)
−
1
4
=
5
6
⇒
⇒
P
(
B
)
=
1
3
⇒
Now,
P
(
A
∩
B
)
=
1
4
,
P
(
A
)
=
3
4
and
P
(
B
)
=
1
3
P
⇒
P
(
A
∩
B
)
=
P
(
A
)
P
(
B
)
and
P
(
A
)
≠
P
(
B
)
⇒
⇒
⇒
A and B independen but not equally likely.