Correct Answer - B
Since x and y each can take values from 0 to 10. So, the total number of ways of selecting x and y is
11
×
11
=
121
11
.
Now,
|
x
,
y
|
>
5
⇒
⇒
x
−
y
<
−
5
or
,
x
−
y
>
5
|
There are 30 pairs of values of x and y satisfying these two inequalities,
So, favourable number of elementary events=30.
Hence, required probability
=
30
121
=