Correct Answer - (i)5:31(ii)5:1
n(S)=(6×6)=36
.
(i) Let E1
= event of getting the sum 6
={(1,5),(2,4),(3,3),(4,2),(5,1)}
⇒n(E1)=5.
Thus, E1
occurs in 5 ways and does not occur in (36 - 5) = 31 ways.
∴
odds in favour of getting the sum 6=5:31.
(ii) Let E2
= event of getting the sum 7
={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}
⇒n(E2)=6
.
Thus, E2
occurs in 6 ways and does not occur in (36 - 60 = 30 ways.
∴
odds against getting the sum 7=30:6=5:1
.
