Let A denotes Apples and O denotes Oranges and it is given that there are 20 apples and 10 oranges.
Out of 20 apples 5 and 10 oranges 3 are defective.
`P(AUB)=P(A)+P(B)-P(AnnB)`
`n(A)=(20C_2)`
`P(A)=(20C_2)/(30C_2)`
`n(B)=22C_2`
`P(B)=(22C_2)/(30C_2)`
`n(AnnB)=15C_2`
`P(AnnB)=(15C_2)/(30C_2)`
`P(AUB)= (20C_2)/(30C_2)+(22C_2)/(30C_2)-(15C_2)/(30C_2)`
`P(AUB)=0.72`