(i) Let `E_(1)` and `E_(2)` be mutially exclusive. Then `E_(1) nn E_(2)= varphi`.
`:. P(E_(1) uu E_(2))=P(E_(1))+P(E_(2))`
`implies 0.4=0.3+x`
`implies x=0.1`
Thus, when `E_(1)` and `E_(2)` mutually exclusive, then `x=0.1`.
(ii) Let `E_(1)` and `E_(2)` be two independent events. Then.
`P(E_(1) nn E_(2))=P(E_(1))xxP(E_(2))=0.3xx x=0.3 x`.
`:. P(E_(1) uu E_(2))=P(E_(1))+P_(E_(2))-P(E_(1) nn E_(2))`
`implies 0.4=0.3+x-0.3 x`
`implies 0.7 x=0.1`
`implies x=0.1/0.7=1/7`
Thus, when `E_(1)` and `E_(2)` are independent, then `x=1/7`.