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If the probability for A to fail in an examination is 0.2 and that for B is 0.3, then the probability that either A or B fails, is (A) 0.38 (B) 0.44 (C) 0.50 (D) 0.94 Select the correct answer from above options

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Given , P(A fails in examination)=0.2 and P(B fails in examination)=0.3 P(A∩N)=P(A)P(B)=(0.2)(0.3) ∴P(A∪B)=P(A)+P(B)-P(A∩B) 0.2+0.3-0.06=0.44 Hence, it is a false statement.

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