Correct Answer - C
Let E= event when each American man is seated adjacent to his ****
and A=event when Indian man is seated adjacent to his ****
Now , n(A∩E)=(4!)×(2!)5
Even when each American man is seated adjacent to his ****.
Again , n(E)=(5!)×(2!)4
∴P(
A
E
)=
n(A∩E)
n(E)
=
(4!)×(2!)5
(5!)×(2!)4
=
2
5
Alternate solution
Fixing four American couples and one Indian man in between any two couples , we have 5 different ways in which his **** can be seated , of which 2 cases are favourable.
∴ Required probability =
2
5
