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Three are 8 brown balls ,4 orange balls and 5 blacks balls in a bag .Five balls are chosen at random. What is the probability of their being 2 brown balls ,I orange ball and 2 black balls ? A. 191 1547 B. 180 1547 C. 280 1547 D. 189 1547 Select the correct answer from above options

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Correct Answer - C Total possible outcomes = 17 C 5 = = 17 × 16 × 15 × 14 × 13 1 × 2 × 3 × 4 × 5 = 6188 = Total favourable outcomes = 8 C 2 × 4 C 1 × 5 C 2 Total favourable outcomes = 8 × 7 1 × 2 × 4 s s 5 × 4 1 × 2 = 28 × 4 × 10 = 1120 = Required probability = 1120 6188 = 280 1547 =

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