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Given E = 40xyi + 20x^2j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3).

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Given E = 40xyi + 20x^2j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3). (a) 105 (b) 106 (c) 107 (d) 108 The question was asked in unit test. My question is from Electric Potential in section Electrostatic Fields of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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The correct answer is (b) 106 For explanation: V = -∫ E.dl = -∫ (40xy dx + 20x^2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get Vpq on integrating from Q to P. Vpq = 106 volts.

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