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The force per unit length of two conductors carrying equal currents of 5A separated by a distance of 20cm in air(in 10^-6 order) (a) 25 (b) 35 (c) 40 (d) 50 I got this question during an online exam. This intriguing question comes from Magnetic Force and Lorentz Force in division Magnetic Forces and Materials of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right choice is (a) 25 The best explanation: The force per unit length of two conductors is given by F = μ I1xI2/2πD, where I1 = I2 = 5 and D = 0.2. Thus F = 4π x 10^-7 x 52/ 2π x 0.2 = 25 x 10^-6 units.

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