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Calculate the flux density due to a circular conductor of radius 100nm and current 5A in air. (a) 10 (b) 100 (c) 0.1 (d) 1 I had been asked this question during an interview for a job. Origin of the question is Magnetization in portion Magnetic Forces and Materials of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

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Right choice is (a) 10 The explanation is: The field intensity of this conductor is I/2πR and since B = μH, the flux density will be B = μI/2πR. Put I = 5 and R = 100 x 10^-9, thus we get B = 4π x 10^-7x 5/(2π x 100 x 10^-9) = 10 units.

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