Question

The power of a wave of with voltage of 140V and a characteristic impedance of 50 ohm is (a) 1.96 (b) 19.6 (c) 196 (d) 19600 The question was asked in an online interview. My doubt is from Power, Power Loss and Return Loss topic in chapter EM Wave Propagation of Electromagnetic Theory Select the correct answer from above options Electromagnetic Theory questions and answers, Electromagnetic Theory questions pdf, Electromagnetic Theory question bank, Electromagnetic Theory questions and answers pdf, mcq on Electromagnetic Theory pdf,electromagnetic theory book pdf,electromagnetic theory pdf notes,electromagnetic theory lecture notes,electromagnetic theory of light,maxwell electromagnetic theory,electromagnetic theory proposed by,electromagnetic theory engineering physics,electromagnetic theory nptel

Answer 1

The correct answer is (c) 196 Best explanation: The power of a wave is given by P = V^2/2Zo, where V is the generator voltage and Zo is the characteristic impedance. on substituting the given data, we get P = 140^2/(2×50) = 196 units.