Question

A 25 Ω resistor has a voltage of 150 sin377 t. Find the corresponding power. (a) 900 sin^2 337 t (b) 90 sin^2 337 t (c) 900 sin^2 377 t (d) 9 sin^2 337 t This question was posed to me by my college professor while I was bunking the class. This interesting question is from Basic Network Concepts topic in section Circuit Elements and Kirchhoff’s Laws of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right answer is (c) 900 sin^2 377 t The explanation: Given R = 25 Ω and v = 150 sin 377 t i = \frac{v}{R} = \frac{150 sin⁡ 377 t}{25} = 6 sin 377 t p = vi = (150 sin 377 t)(6 sin 377 t) = 900 sin^2 377 t.