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In the following circuit, the value of Norton’s resistance between terminals a and b are ___________ (a) RN = 1800 Ω (b) RN = 270 Ω (c) RN = 90 Ω (d) RN = 90 Ω I had been asked this question by my school principal while I was bunking the class. This intriguing question originated from Norton’s Theorem Involving Dependent and Independent Sources topic in division Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

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Right option is (d) RN = 90 Ω Explanation: By writing loop equations for the circuit, we get, VS = VX, IS = IX VS = 600(I1 – I2) + 300(I1 – I2) + 900 I1 = (600+300+900) I1 – 600I2 – 300I3 = 1800I1 – 600I2 – 300I3 I1 = IS, I2 = 0.3 VS I3 = 3IS + 0.2VS VS = 1800IS – 600(0.01VS) – 300(3IS + 0.01VS) = 1800IS – 6VS – 900IS – 3VS 10VS = 900IS For Voltage, VS = RN IS + VOC Here VOC = 0 So, Resistance RN = 90Ω.

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