Question

The Norton equivalent impedance Z between the nodes P and Q in the following circuit is __________ (a) 1 (b) 1 + s + \(\frac{1}{s}\) (c) 2 + s + \(\frac{1}{s}\) (d) 3 + s + \(\frac{1}{s}\) I had been asked this question at a job interview. Question is taken from Norton’s Theorem Involving Dependent and Independent Sources in section Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct answer is (a) 1 The explanation is: To calculate the Norton resistance, all the current sources get open-circuited and voltage sources get short-circuited. ∴ RN = (\(\frac{1}{s}\) + 1) || (1+s) = \(\frac{\left(\frac{1}{s} + 1\right)×(1+s)}{\left(\frac{1}{s} + 1\right)+(1+s)}\) = \(\frac{\frac{1}{s}+1+1+s}{\frac{1}{s}+1+1+s}\) = 1 So, RN = 1.