Question

In the circuit shown below what is the value of RL for which maximum power is transferred to RL? (a) 2.4 Ω (b) \(\frac{8}{3}\) Ω (c) 4 Ω (d) 6 Ω This question was addressed to me in an interview for job. This intriguing question comes from Advanced Problems on Millman’s Theorem and Maximum Power Transfer Theorem topic in portion Useful Theorems in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

Right option is (c) 4 Ω The explanation is: Maximum power is transferred to RL when the load resistance equals the Thevenin resistance of the circuit. RL = RTH = \(\frac{V_{OC}}{I_{SC}} \) Due to open-circuit, VOC = 100 V; ISC = I1 + I2 Applying KVL in lower loop, 100 – 8I1 = 0 Or, I1 = \(\frac{100}{8} = \frac{25}{2}\) And VX = -4I1 = -4 × \(\frac{25}{2}\) = -50V KVL in upper loop, 100 + VX – 4I2 = 0 I2 = \(\frac{100-50}{4} = \frac{25}{2}\) Hence, ISC = I1 + I2 = \(\frac{25}{2} + \frac{25}{2}\) = 25 RTH = \(\frac{V_{OC}}{I_{SC}} = \frac{100}{25}\) = 4 Ω RL = RTH = 4 Ω.