Question

In the figure given below, what is the RMS value of the periodic waveform? (a) 2\sqrt{6} A (b) 6\sqrt{2} A (c) \sqrt{\frac{4}{3}} A (d) 1.5 A This question was addressed to me in a job interview. My query is from Dot Convention in Magnetically Coupled Circuits topic in section Resonance & Magnetically Coupled Circuit of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct option is (a) 2\sqrt{6} A The explanation is: The rms value for any waveform is = \sqrt{\frac{1}{T} \int_0^T f^2 (t)dt)} = [\frac{1}{T}(\int_0^{\frac{T}{2}}(mt)^2 dt + \int_{\frac{T}{2}}^T 6^2 dt]^{1/2} = [\frac{1}{T}(\frac{144}{T^2} × \frac{T^3}{3×8} + 36 × \frac{T}{2})]^{\frac{1}{2}} = [6+18]^{\frac{1}{2}} = \sqrt{24} = 2\sqrt{6} A.