Question

In the circuit given below, the voltage across R by mesh analysis is _________ (a) 1.59 V (b) 1 V (c) 2.54 V (d) 1.54 V The question was asked during an online interview. I'm obligated to ask this question of Calculation of I(0+), di/dt(0+), d2I/dt2(0+) in Circuits Involving both Capacitor and Inductor topic in chapter Application of the Laplace Transform in Circuit Analysis of Network Theory Select the correct answer from above options network theory questions and answers, network theory questions pdf, network theory question bank, network theory gate questions and answers pdf, mcq on network theory pdf, gate network theory questions and solutions, network theory mcq Test , ies network theory questions, Network theory Questions for GATE EC Exam, Network Theory MCQ (Multiple Choice Questions)

Answer 1

The correct choice is (d) 1.54 V The explanation is: In loop 1, by KVL, (10 + 2) I1 + (-2) I2 + 0I3 = 5 Or, 12 I1 – 2I2 = 5 In loop 2, -2I1 + (10+2+20+2) I2 + (-2) I3 = 0 Or, -2I1 + 34 I2 – 2I3 = 0 In loop 3, 0I1 + – 2I2 + (2+10) I3 = 10 Or, 0I1 – 2I2 + 12I3 = 10 Now, the voltage across R is VR = (I2 – I3) R Now, I2 = \frac{360}{4800} = \frac{3}{40} Now, I3 = \frac{4060}{4800} = \frac{203}{240} A Therefore, VR = (I2 – I3) R = \Big[\frac{3}{40} – \frac{203}{240}\Big] 2 = 1.54 V.